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X^2+30X-117=0
a = 1; b = 30; c = -117;
Δ = b2-4ac
Δ = 302-4·1·(-117)
Δ = 1368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1368}=\sqrt{36*38}=\sqrt{36}*\sqrt{38}=6\sqrt{38}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{38}}{2*1}=\frac{-30-6\sqrt{38}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{38}}{2*1}=\frac{-30+6\sqrt{38}}{2} $
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